Unique Face Auction 10
Old 07-09-2012, 08:15 AM   #1
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Default Unique Face Auction 10

We are currently auctioning off the ability to have a truly unique face in Nodiatis. Players may make a bid to receive any of the faces below - once a face has been won via auction it will never be available again. The winning player will be the only one to ever be able to use that face. Players may also opt to provide a 128x128 transparent PNG of a custom face, however, the face must be original artwork (ie not taken from another game or internet image) and must be an actual portrait. Players can also provide a 128x128 original background image to be used with their face.



To submit a bid simply make a post below with your bid in Time Cards. Do not post in this thread unless you are making a bid, make a seperate thread for face auction discussion/questions.

Make sure all bids made are legit.

We will start the bid at 10 TCs. Bidding will end on or before Tuesday. Bid early, don't wait until the last minute.
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Computing the probability that at least one of the following events will occur:
P(a or b ... or z) = 1 - P(!a and !b ... and !z)
Probability
 

Old 07-09-2012, 08:16 AM   #2
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10
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Old 07-09-2012, 08:16 AM   #3
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15
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I TURN WOMEN GAY....!!
 

Old 07-09-2012, 08:17 AM   #4
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25
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http://www.freewebs.com/flashusrollus...the 1st help site for Nodiatis
 

Old 07-09-2012, 08:20 AM   #5
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Ok, 31 here, and paying 5 tc's if i win for a nice artwork
 

Old 07-10-2012, 02:42 PM   #6
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35 tcs
 

Old 07-10-2012, 07:14 PM   #7
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36
 

Old 07-10-2012, 07:14 PM   #8
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37
 

Old 07-10-2012, 07:15 PM   #9
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38 =p
 

Old 07-10-2012, 07:15 PM   #10
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Bid DQ'ed, was not high enough to beat last bid.
 

Old 07-10-2012, 07:16 PM   #11
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40
 

Old 07-10-2012, 07:16 PM   #12
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41
 

Old 07-10-2012, 07:17 PM   #13
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Old 07-10-2012, 07:17 PM   #14
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45
 

Old 07-10-2012, 07:17 PM   #15
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46
 

Old 07-10-2012, 07:17 PM   #16
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Old 07-10-2012, 07:17 PM   #17
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50
 

Old 07-10-2012, 07:18 PM   #18
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Old 07-10-2012, 07:18 PM   #19
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Auction ends in 60 seconds.
__________________
Computing the probability that at least one of the following events will occur:
P(a or b ... or z) = 1 - P(!a and !b ... and !z)
Probability
 

Old 07-10-2012, 07:18 PM   #20
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